Write in Logarithmic Form$81^{-3 / 2}=\frac{1}{729}$ A)$\log _{81}\left(\frac{3}{2}\right)=-\frac{1}{729}$ B)$\log _{81}\left(\frac{1}{729}\right)=-\frac{3}{2}$

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The Answer of Write in Logarithmic Form$81^{-3 / 2}=\frac{1}{729}$ A)$\log _{81}\left(\frac{3}{2}\right)=-\frac{1}{729}$ B)$\log _{81}\left(\frac{1}{729}\right)=-\frac{3}{2}$

Write in Logarithmic Form $81^{-3 / 2}=\frac{1}{729}$ A) $\log _{81}\left(\frac{3}{2}\right)=-\frac{1}{729}$ B) $\log _{81}\left(\frac{1}{729}\right)=-\frac{3}{2}$

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Write in Logarithmic Form 81−3/2=172981^{-3 / 2}=\frac{1}{729}81−3/2=7291​ A) log⁡81(32)=−1729\log _{81}\left(\frac{3}{2}\right)=-\frac{1}{729}log81​(23​)=−7291​ B) log⁡81(1729)=−32\log _{81}\left(\frac{1}{729}\right)=-\frac{3}{2}log81​(7291​)=−23​

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Write in Logarithmic Form $81^{-3 / 2}=\frac{1}{729}$ A) $\log _{81}\left(\frac{3}{2}\right)=-\frac{1}{729}$ B) $\log _{81}\left(\frac{1}{729}\right)=-\frac{3}{2}$

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