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Using a Table of Laplace Transforms, Find the Inverse Transform F(s)=1s2+10s+29F(s)=\frac{1}{s^{2}+10 s+29}

Question 14

Multiple Choice

Using a table of Laplace transforms, find the inverse transform of F(s) =1s2+10s+29F(s) =\frac{1}{s^{2}+10 s+29} .


A) f(t) =12e2tsin5tf(t) =\frac{1}{2} e^{-2 t} \sin 5 t

B) f(t) =e2tcos5tf(t) =e^{-2 t} \cos 5 t

C) f(t) =e2tsin5tf(t) =e^{-2 t} \sin 5 t

D) f(t) =12e2tcos5tf(t) =\frac{1}{2} e^{-2 t} \cos 5 t

Correct Answer:

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