Solve Simultaneously $x+\frac{2 x-y+1}{9 y}=\frac{-16}{9}$ $\frac{x-3 y+1}{2}-\frac{x-2 y}{3}=1$

Short Answer

Solve simultaneously: $x+\frac{2 x-y+1}{9 y}=\frac{-16}{9}$
$\frac{x-3 y+1}{2}-\frac{x-2 y}{3}=1$