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    Exam 10: Systems of Linear Equations
  5. Question
    Solve\(x+2 y-z=4\) \(\begin{aligned} & 2 x-y-3 z=-19 \\ & x+5 y+2 z=25 \end{aligned}\)
Solved

Solve x+2y−z=4x+2 y-z=4x+2y−z=4 2x−y−3z=−19x+5y+2z=25\begin{aligned}& 2 x-y-3 z=-19 \\& x+5 y+2 z=25\end{aligned}​2x−y−3z=−19x+5y+2z=25​

Question 60

Question 60

Short Answer

Solve: x+2y−z=4x+2 y-z=4x+2y−z=4
2x−y−3z=−19x+5y+2z=25\begin{aligned}& 2 x-y-3 z=-19 \\& x+5 y+2 z=25\end{aligned}​2x−y−3z=−19x+5y+2z=25​

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