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Solve Leave Your Answers in Fractional Form 1x+2y2z=6\frac{1}{x}+\frac{2}{y}-\frac{2}{z}=6 1x+1y=72y1z=3\begin{aligned}& \frac{1}{x}+\frac{1}{y}=7 \\& \frac{2}{y}-\frac{1}{z}=3\end{aligned}

Question 29

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Solve. Leave your answers in fractional form: 1x+2y2z=6\frac{1}{x}+\frac{2}{y}-\frac{2}{z}=6
1x+1y=72y1z=3\begin{aligned}& \frac{1}{x}+\frac{1}{y}=7 \\& \frac{2}{y}-\frac{1}{z}=3\end{aligned}

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