A Projectile Is Launched from Height $h_{o}$ Above the Ground $t$ Seconds Is Given By

Short Answer

A projectile is launched from height $h_{o}$ above the ground. Its height (metres) after $t$ seconds is given by $s=k t^{2}+v_{0} t+h_{0}$ where $k$ is a constant, $v_{0}$ is the initial velocity. If the height at $1.0 \mathrm{~s}$ is $7.75 \mathrm{~m}$ and the height at $1.5 \mathrm{~s}$ is $6.625 \mathrm{~m}$ , and the height at $2.0 \mathrm{~s}$ is $5.00 \mathrm{~m}$ , determine the height at time $2.5 \mathrm{~s}$ .