Solve For $x$ To Three Significant Digits $\log x=\log _{10} x$ ] $\log (2 x-3)-\log (3 x+2)=\log (4 x-7)-\log (6 x-5)$

Short Answer

Solve for $x$ to three significant digits. Check your answers.
[HINT: $\log x=\log _{10} x$ ]
$\log (2 x-3)-\log (3 x+2)=\log (4 x-7)-\log (6 x-5)$