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Solve For xx log⁡x3=2+log⁡x2−log⁡x\log x^{3}=\frac{2+\log x}{2-\log x}

Question 5

Short Answer

Solve for xx : log⁡x3=2+log⁡x2−log⁡x\log x^{3}=\frac{2+\log x}{2-\log x}

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