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Solve the Problem tt Seconds Is f(t)=18t+1+13t2+1f(t)=\frac{18}{t+1}+\frac{13}{t^{2}+1} Feet What Is the Instantaneous Velocity at 2 Seconds?
A)

Question 180

Multiple Choice

Solve the problem.
-A particle is moving on a horizontal line. Its distance from the origin at time tt seconds is f(t) =18t+1+13t2+1f(t) =\frac{18}{t+1}+\frac{13}{t^{2}+1} feet. What is the instantaneous velocity at 2 seconds?


A) 145ft/sec-\frac{14}{5} \mathrm{ft} / \mathrm{sec}
B) 435ft/sec\frac{43}{5} \mathrm{ft} / \mathrm{sec}
C) 709ft/sec-\frac{70}{9} \mathrm{ft} / \mathrm{sec}
D) 10225ft/sec-\frac{102}{25} \mathrm{ft} / \mathrm{sec}

Correct Answer:

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