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    Quantitative Chemical Analysis
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    Exam 14: Advanced Topics in Equilibrium
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Question 11

Question 11

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A solution is 0.200 M in acetic acid and 0.100 M KCl.Calculate the concentration acetic acid and acetate in solution for a pH 4.500. A solution is 0.200 M in acetic acid and 0.100 M KCl.Calculate the concentration acetic acid and acetate in solution for a pH 4.500.   = 0.775,   = 1,   = 0.83 and K<sub>a</sub> = 1.75 × 10<sup>−</sup><sup>5</sup>. = 0.775, A solution is 0.200 M in acetic acid and 0.100 M KCl.Calculate the concentration acetic acid and acetate in solution for a pH 4.500.   = 0.775,   = 1,   = 0.83 and K<sub>a</sub> = 1.75 × 10<sup>−</sup><sup>5</sup>. = 1, A solution is 0.200 M in acetic acid and 0.100 M KCl.Calculate the concentration acetic acid and acetate in solution for a pH 4.500.   = 0.775,   = 1,   = 0.83 and K<sub>a</sub> = 1.75 × 10<sup>−</sup><sup>5</sup>. = 0.83 and Ka = 1.75 × 10−5.

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