Multiple Choice
How many grams of CaCl2 are formed when 15.00 mL of 0.00237 M Ca(OH) 2 reacts with excess Cl2 gas?
2 Ca(OH) 2(aq) + 2 Cl2(g) → Ca(OCl) 2(aq) + CaCl2(s) + 2 H2O(l)
A) 0) 00 197 g
B) 0) 00 394 g
C) 0) 0 0789 g
D) 0) 0 507 g
Correct Answer:
Verified
Correct Answer:
Verified
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