Given: Pb(s)+ PbO 2 (s)+ 2H 2 SO 4 (l)→ 2PbSO 4 (s)+ 2H 2 O(l); ΔH° = -509.2 KJ

The Answer of Given: Pb(s)+ PbO 2 (s)+ 2H 2 SO 4 (l)→ 2PbSO 4 (s)+ 2H 2 O(l); ΔH° = -509.2 KJ

Given: Pb(s)+ PbO 2 (s)+ 2H 2 SO 4 (l)→ 2PbSO 4 (s)+ 2H 2 O(l); ΔH° = -509.2 KJ

The Answer of Given: Pb(s)+ PbO 2 (s)+ 2H 2 SO 4 (l)→ 2PbSO 4 (s)+ 2H 2 O(l); ΔH° = -509.2 KJ

Solved

Given: Pb(s)+ PbO₂(s)+ 2H₂SO₄(l)→ 2PbSO₄(s)+ 2H₂O(l); ΔH° = -509.2 KJ

Question 98

Multiple Choice

Given:
Pb(s) + PbO₂(s) + 2H₂SO₄(l) → 2PbSO₄(s) + 2H₂O(l) ; ΔH° = -509.2 kJ
SO₃(g) + H₂O(l) → H₂SO₄(l) ; ΔH° = -130.kJ
Determine ΔH° for the following thermochemical equation.
Pb(s) + PbO₂(s) + 2SO₃(g) → 2PbSO₄(s)

A) 3.77 × 10³ kJ
B) -521 kJ
C) -3.77 × 10³ kJ
D) -639 kJ
E) -769 kJ

Given: Pb(s)+ PbO2(s)+ 2H2SO4(l)→ 2PbSO4(s)+ 2H2O(l); ΔH° = -509.2 KJ

Multiple Choice

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Given: Pb(s)+ PbO₂(s)+ 2H₂SO₄(l)→ 2PbSO₄(s)+ 2H₂O(l); ΔH° = -509.2 KJ

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