For CdO(s)+ SO 3 (g)→ CdSO 4 (s),Δ r H° = -279

The Answer of For CdO(s)+ SO 3 (g)→ CdSO 4 (s),Δ r H° = -279

The Answer of For CdO(s)+ SO 3 (g)→ CdSO 4 (s),Δ r H° = -279

Solved

For CdO(s)+ SO₃(g)→ CdSO₄(s),Δ_rH° = -279

Question 54

For CdO(s) + SO₃(g) → CdSO₄(s) ,Δ_rH° = -279.4 kJ/mol,and Δ_rS° = -118.4 J/mol K.What is Δ_rG° in kJ/mol at 127 K?

A) -256 kJ/mol
B) -303 kJ/mol
C) -264 kJ/mol
D) -355 kJ/mol
E) -460 kJ/mol

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