For CdO(s)+ SO 3 (g)→ CdSO 4 (s),Δ r H° = -279

The Answer of For CdO(s)+ SO 3 (g)→ CdSO 4 (s),Δ r H° = -279

The Answer of For CdO(s)+ SO 3 (g)→ CdSO 4 (s),Δ r H° = -279

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For CdO(s)+ SO₃(g)→ CdSO₄(s),Δ_rH° = -279

Question 116

For CdO(s) + SO₃(g) → CdSO₄(s) ,Δ_rH° = -279.4 kJ/mol,and Δ_rS° = -118.4 J/mol ∙ K.What is the temperature at which K_eq is 1.0 × 10⁴?

A) 1890 °C
B) 6950 °C
C) 1160 °C
D) 1710 °C
E) 6410 °C

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