Multiple Choice
A pH 4.88 buffer was prepared by dissolving 0.10 mol of benzoic acid (Ka = 6.3 × 10-5) and 0.50 mol of sodium benzoate in sufficient pure water to form a 1.00 L solution.To a 70.0 mL aliquot of this solution was added 2.00 mL of 2.00 M aqueous HI solution.What was the pH of the new 72.0 mL solution?
A) 2.84
B) 3.16
C) 3.36
D) 4.65
E) 4.90
Correct Answer:

Verified
Correct Answer:
Verified
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