The Solubility Product Constant of PbI₂(s)is 7

Multiple Choice

The solubility product constant of PbI₂(s) is 7.1 × 10^-9.How many moles of PbI₂ will precipitate if 250 mL of a 0.200 M solution of NaI(aq) are added to 150 mL of 0.100 M solution of Pb(NO₃) ₂(aq) ? You may neglect hydrolysis.

A) 0.050 mol
B) 1.3 × 10^-5 mol
C) 0.015 mol
D) 5.6 × 10^-3 mol
E) 0.040 mol