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    Exam 19: Electrochemistry
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    Determine E°<sub>cell</sub> for the Reaction: Pb<sup>2+</sup>(aq)+ Zn(s)→ Pb(s)+ Zn<sup>2+</sup>(aq)
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Determine E°cell for the Reaction: Pb2+(aq)+ Zn(s)→ Pb(s)+ Zn2+(aq)

Question 87

Question 87

Multiple Choice

Determine E°cell for the reaction: Pb2+(aq) + Zn(s) → Pb(s) + Zn2+(aq) .The half reactions are:
Pb2+(aq) + 2 e- → Pb(s) E° = -0.125 V
Zn2+(aq) + 2 e- → Zn(s) E° = -0.763 V


A) 0.638 V
B) -0.638 V
C) 0.888 V
D) -1.276 V
E) -0.888 V

Correct Answer:

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