Short Answer
The enthalpy of combustion of acetylene C2H2 is described by
C2H2(g)+ (5/2)O2(g) 2CO2(g)+ H2O(l), H°rxn= -1299 kJ/mol
Calculate the enthalpy of formation of acetylene, given the following enthalpies of formation
H°f[CO2(g)] = -393.5 kJ/mol
H°f[H2O(l)] = -285.8 kJ/mol
Correct Answer:

Verified
Correct Answer:
Verified
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