Short Answer
What would be the standard enthalpy change for the reaction of 1.00 mole of H2(g)with 1.00 mole of Cl2(g)to produce 2.00 moles of HCl(g)at standard state conditions?
H°f (HCl(g))= -92.3 kJ/mol]
Correct Answer:

Verified
Correct Answer:
Verified
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