Methanol (CH 3 OH)burns According to the Equation 2CH 3 OH(l)+ 3O 2 (g)$\rarr$ 2CO 2 (g)+ 4H 2 O(l)$\Delta$

The Answer of Methanol (CH 3 OH)burns According to the Equation 2CH 3 OH(l)+ 3O 2 (g)$\rarr$ 2CO 2 (g)+ 4H 2 O(l)$\Delta$

Methanol (CH 3 OH)burns According to the Equation 2CH 3 OH(l)+ 3O 2 (g)$\rarr$ 2CO 2 (g)+ 4H 2 O(l)$\Delta$

The Answer of Methanol (CH 3 OH)burns According to the Equation 2CH 3 OH(l)+ 3O 2 (g)$\rarr$ 2CO 2 (g)+ 4H 2 O(l)$\Delta$

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Methanol (CH₃OH)burns According to the Equation 2CH₃OH(l)+ 3O₂(g) $\rarr$ 2CO₂(g)+ 4H₂O(l) $\Delta$

Question 71

Multiple Choice

Methanol (CH₃OH) burns according to the equation 2CH₃OH(l) + 3O₂(g) $\rarr$ 2CO₂(g) + 4H₂O(l) , $\Delta$ H°_rxn = -1454 kJ/mol.
How much heat, in kilojoules, is given off when 75.0 g of methanol is burned?

A) 727 kJ
B) 3.22 * 10³ kJ
C) 1.45 * 10³ kJ
D) 1.70 * 10^-3 kJ
E) 3.41 * 10³ kJ

Methanol (CH3OH)burns According to the Equation 2CH3OH(l)+ 3O2(g) →\rarr→ 2CO2(g)+ 4H2O(l) Δ\DeltaΔ

Multiple Choice

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Methanol (CH₃OH)burns According to the Equation 2CH₃OH(l)+ 3O₂(g) $\rarr$ 2CO₂(g)+ 4H₂O(l) $\Delta$

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