At 25°C, the Standard Enthalpy of Formation of KCl(s)is -435 $\Delta$

Multiple Choice

At 25°C, the standard enthalpy of formation of KCl(s) is -435.87 kJ/mol. When one mole of KCl(s) is formed by reacting potassium vapor and chlorine gas at 25°C, the standard enthalpy of reaction is -525.86 kJ/mol. Find $\Delta$ H° for the sublimation of potassium, K(s) $\rarr$ K(g) , at 25°C.

A) -345.88 kJ/mol
B) 45.00 kJ/mol
C) 345.88 kJ/mol
D) 89.99 kJ/mol
E) -525.86 kJ/mol