Solved

A Two-Sample Z-Test for Two Population Proportions Is to Be

Question 20

Multiple Choice

A two-sample z-test for two population proportions is to be performed using the P-value approach.The null hypothesis is A two-sample z-test for two population proportions is to be performed using the P-value approach.The null hypothesis is : = and the alternative is : ≠ .Use the given sample data to find the P-value for the hypothesis test.Give an interpretation of the p-value. -A university found it retained 25 students out of 352 in 2009 and 36 students out of 334 in 2010. A) P-value = 0.0455;If there is no difference in the proportions,there is about a 4.55% chance of seeing the observed difference or larger by natural sampling variation. B) P-value = 0.9545;If there is no difference in the proportions,there is about a 95.45% chance of seeing the observed difference or larger by natural sampling variation. C) P-value = 0.0455;There is about a 4.55% chance that the two proportions are equal. D) P-value = 0.091;There is about a 9.1% chance that the two proportions are equal. E) P-value = 0.091;If there is no difference in the proportions,there is about a 9.1% chance of seeing the observed difference or larger by natural sampling variation.
: A two-sample z-test for two population proportions is to be performed using the P-value approach.The null hypothesis is : = and the alternative is : ≠ .Use the given sample data to find the P-value for the hypothesis test.Give an interpretation of the p-value. -A university found it retained 25 students out of 352 in 2009 and 36 students out of 334 in 2010. A) P-value = 0.0455;If there is no difference in the proportions,there is about a 4.55% chance of seeing the observed difference or larger by natural sampling variation. B) P-value = 0.9545;If there is no difference in the proportions,there is about a 95.45% chance of seeing the observed difference or larger by natural sampling variation. C) P-value = 0.0455;There is about a 4.55% chance that the two proportions are equal. D) P-value = 0.091;There is about a 9.1% chance that the two proportions are equal. E) P-value = 0.091;If there is no difference in the proportions,there is about a 9.1% chance of seeing the observed difference or larger by natural sampling variation.
= A two-sample z-test for two population proportions is to be performed using the P-value approach.The null hypothesis is : = and the alternative is : ≠ .Use the given sample data to find the P-value for the hypothesis test.Give an interpretation of the p-value. -A university found it retained 25 students out of 352 in 2009 and 36 students out of 334 in 2010. A) P-value = 0.0455;If there is no difference in the proportions,there is about a 4.55% chance of seeing the observed difference or larger by natural sampling variation. B) P-value = 0.9545;If there is no difference in the proportions,there is about a 95.45% chance of seeing the observed difference or larger by natural sampling variation. C) P-value = 0.0455;There is about a 4.55% chance that the two proportions are equal. D) P-value = 0.091;There is about a 9.1% chance that the two proportions are equal. E) P-value = 0.091;If there is no difference in the proportions,there is about a 9.1% chance of seeing the observed difference or larger by natural sampling variation.
and the alternative is A two-sample z-test for two population proportions is to be performed using the P-value approach.The null hypothesis is : = and the alternative is : ≠ .Use the given sample data to find the P-value for the hypothesis test.Give an interpretation of the p-value. -A university found it retained 25 students out of 352 in 2009 and 36 students out of 334 in 2010. A) P-value = 0.0455;If there is no difference in the proportions,there is about a 4.55% chance of seeing the observed difference or larger by natural sampling variation. B) P-value = 0.9545;If there is no difference in the proportions,there is about a 95.45% chance of seeing the observed difference or larger by natural sampling variation. C) P-value = 0.0455;There is about a 4.55% chance that the two proportions are equal. D) P-value = 0.091;There is about a 9.1% chance that the two proportions are equal. E) P-value = 0.091;If there is no difference in the proportions,there is about a 9.1% chance of seeing the observed difference or larger by natural sampling variation.
: A two-sample z-test for two population proportions is to be performed using the P-value approach.The null hypothesis is : = and the alternative is : ≠ .Use the given sample data to find the P-value for the hypothesis test.Give an interpretation of the p-value. -A university found it retained 25 students out of 352 in 2009 and 36 students out of 334 in 2010. A) P-value = 0.0455;If there is no difference in the proportions,there is about a 4.55% chance of seeing the observed difference or larger by natural sampling variation. B) P-value = 0.9545;If there is no difference in the proportions,there is about a 95.45% chance of seeing the observed difference or larger by natural sampling variation. C) P-value = 0.0455;There is about a 4.55% chance that the two proportions are equal. D) P-value = 0.091;There is about a 9.1% chance that the two proportions are equal. E) P-value = 0.091;If there is no difference in the proportions,there is about a 9.1% chance of seeing the observed difference or larger by natural sampling variation.
≠ A two-sample z-test for two population proportions is to be performed using the P-value approach.The null hypothesis is : = and the alternative is : ≠ .Use the given sample data to find the P-value for the hypothesis test.Give an interpretation of the p-value. -A university found it retained 25 students out of 352 in 2009 and 36 students out of 334 in 2010. A) P-value = 0.0455;If there is no difference in the proportions,there is about a 4.55% chance of seeing the observed difference or larger by natural sampling variation. B) P-value = 0.9545;If there is no difference in the proportions,there is about a 95.45% chance of seeing the observed difference or larger by natural sampling variation. C) P-value = 0.0455;There is about a 4.55% chance that the two proportions are equal. D) P-value = 0.091;There is about a 9.1% chance that the two proportions are equal. E) P-value = 0.091;If there is no difference in the proportions,there is about a 9.1% chance of seeing the observed difference or larger by natural sampling variation.
.Use the given sample data to find the P-value for the hypothesis test.Give an interpretation of the p-value.
-A university found it retained 25 students out of 352 in 2009 and 36 students out of 334 in 2010.


A) P-value = 0.0455;If there is no difference in the proportions,there is about a 4.55% chance of seeing the observed difference or larger by natural sampling variation.
B) P-value = 0.9545;If there is no difference in the proportions,there is about a 95.45% chance of seeing the observed difference or larger by natural sampling variation.
C) P-value = 0.0455;There is about a 4.55% chance that the two proportions are equal.
D) P-value = 0.091;There is about a 9.1% chance that the two proportions are equal.
E) P-value = 0.091;If there is no difference in the proportions,there is about a 9.1% chance of seeing the observed difference or larger by natural sampling variation.

Correct Answer:

verifed

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Related Questions

Q5: A poll reported that 3 out of

Q7: In City A,7420 people are unemployed in

Q18: A two-sample z-test for two population proportions

Q22: You wish to construct a 95% confidence

Q23: In a random sample of 500 people

Q25: Use the given sample data to test

Q32: In Canada,a person with a body mass

Q33: You wish to construct a 90% confidence

Q37: A researcher wished to test the claim

Q51: A Member of Parliament wants to measure