Multiple Choice
The esterification of acetic acid and ethanol is given by the reaction below: C2H5OH(aq) + CH3COOH(aq) ⇌ CH3COOC2H5(aq) + H2O(l)
When 1.00 mol of ethanol was mixed with 2.00 mol of acid in a 1.00 L flask,0.86 mol of ester was formed at room temperature.What is the value of the equilibrium constant,Kc?
A) 0.43
B) 2.3
C) 4.6
D) 5.4
Correct Answer:

Verified
Correct Answer:
Verified
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