Multiple Choice
What is the equilibrium constant expression (Ka) for the acid dissociation of hydrocyanic acid HCN? The equation of interest is HCN(aq) + H2O(l) ⇌ H3O+(aq) + CN-(aq) .
A) Ka = ([H3O+][CN-]) /([HCN][H2O])
B) Ka = ([H3O+][CN-]) /([HCN])
C) Ka = ([HCN][H2O]) /([H3O+][CN-])
D) Ka = ([HCN]) /([H3O+][CN-])
Correct Answer:

Verified
Correct Answer:
Verified
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