Multiple Choice
For the decomposition of ammonia to nitrogen and hydrogen, the equilibrium constant is 1.47 *10-6 at 298 K.Calculate the temperature at which K = 0.0100.For this reaction,?H? = 92.38 kJ.mol-1.
A) 241 K
B) 332 K
C) 59 K
D) 390 K
E) 117 K
Correct Answer:

Verified
Correct Answer:
Verified
Related Questions
Q28: When three phases are in mutual equilibrium,such
Q29: Rank the following species in order
Q30: The phase diagram for sulfur is given
Q31: A plot of ln(vapor pressure) versus 1/T
Q32: The normal boiling point of ethanol
Q34: The phase diagram for a pure substance
Q35: Consider the phase diagrams for water and
Q36: If a 1-L flask containing D<sub>2</sub>(g),N<sub>2</sub>(g),and ND<sub>3</sub>(g)at
Q37: Consider the following reaction at a
Q38: For the decomposition of ammonia to nitrogen