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Basic Business Statistics Study Set 1
Exam 10: Hypothesis Testing: Two-Sample Tests
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Question 161
Short Answer
Instruction 10-6 Two samples each of size 25 are taken from independent populations assumed to be normally distributed with equal variances. The first sample has a mean of 35.5 and standard deviation of 3.0 while the second sample has a mean of 33.0 and standard deviation of 4.0. -Referring to Instruction 10-6,a two-tailed test of the null hypothesis of no difference would__________ (be rejected/not be rejecteat the
α
\alpha
α
= 0.05 level of significance.
Question 162
Short Answer
Instruction 10-5 A buyer for a manufacturing plant suspects that his primary supplier of raw materials is overcharging. In order to determine if his suspicion is correct, he contacts a second supplier and asks for the prices on similar various materials. He wants to compare these prices with those of his primary supplier. The data collected is presented in the table below, with some summary statistics presented (all of these might not be necessary to answer the questions which follow). The buyer believes that the differences are normally distributed and will use this sample to perform an appropriate test at a level of significance of 0.01.
Material
Primary Supplier
Secondary
Difference
Supplier
1
$
55
$
45
$
10
2
$
48
$
47
$
1
3
$
31
$
32
−
$
1
4
$
83
$
77
$
6
5
$
37
$
37
$
0
6
$
55
$
54
$
1
Sum:
$
309
$
292
$
17
Sum of Squares:
$
17
,
573
$
15
,
472
$
139
\begin{array}{llll}\text {Material}&\text {Primary Supplier}&\text {Secondary}&\text {Difference}\\&&\text { Supplier }\\ 1 & \$ 55 & \$ 45 & \$ 10 \\2 & \$ 48 & \$ 47 & \$ 1 \\3 & \$ 31 & \$ 32 & -\$ 1 \\4 & \$ 83 & \$ 77 & \$ 6 \\5 & \$ 37 & \$ 37 & \$ 0 \\6 & \$ 55 & \$ 54 & \$ 1 \\\hline \text { Sum: } & \$ 309 & \$ 292 & \$ 17 \\\text { Sum of Squares: } & \$ 17,573 & \$ 15,472 & \$ 139\end{array}
Material
1
2
3
4
5
6
Sum:
Sum of Squares:
Primary Supplier
$55
$48
$31
$83
$37
$55
$309
$17
,
573
Secondary
Supplier
$45
$47
$32
$77
$37
$54
$292
$15
,
472
Difference
$10
$1
−
$1
$6
$0
$1
$17
$139
-Referring to Instruction 10-5,if the buyer had decided to perform a two-tailed test,the p-value would have been between __________ and __________.
Question 163
True/False
Observations that are analysed together on the basis of a common characteristic are known as paired observations.
Question 164
Multiple Choice
Instruction 10-1 Are Chinese managers more motivated than Australian managers? A randomly selected group of each were administered the Sarnoff Survey of Attitudes Toward Life (SSATL) , which measures motivation for upward mobility. The SSATL scores are summarised below.
Australian
Chinese
Sample Size
211
100
Mean SSATL Score
65.75
79.83
Population Std. Dev.
11.07
6.41
\begin{array} { | l | l | l | } \hline & \text { Australian } & \text { Chinese } \\\hline \text { Sample Size } & 211 & 100 \\\hline \text { Mean SSATL Score } & 65.75 & 79.83 \\\hline \text { Population Std. Dev. } & 11.07 & 6.41 \\\hline\end{array}
Sample Size
Mean SSATL Score
Population Std. Dev.
Australian
211
65.75
11.07
Chinese
100
79.83
6.41
-Referring to Instruction 10-1,suppose that the test statistic is Z = 2.45.Find the p-value if we assume that the alternative hypothesis was a two-tailed test (H
1
: ?
A
- ?
J
? 0) .
Question 165
Multiple Choice
In testing for differences between the means of two independent populations,the null hypothesis is
Question 166
Multiple Choice
Instruction 10-10 A few years ago, Pepsi
invited consumers to take the "Pepsi Challenge". Consumers were asked to decide which of the two soft drinks, Coke
or Pepsi, they preferred in a blind taste test. Pepsi was interested in determining what factors played a role in people's taste preferences. One of the factors studied was the gender of the consumer. Below are the results of analyses comparing the taste preferences of men and women with the proportions depicting preference for Pepsi. Males: n = 109,
p
M
p _ { M }
p
M
= 0.422018 Females: n = 52,
p
F
p _ { F }
p
F
= 0.25
p
M
p _ { M }
p
M
-
p
F
p _ { F }
p
F
= 0.172018 Z = 2.11825 -Referring to Instruction 10-10,to determine if a difference exists in the taste preferences of men and women,give the correct alternative hypothesis that Pepsi would test.
Question 167
Multiple Choice
Instruction 10-12 A corporation randomly selects 150 salespeople and finds that 66% who have never taken a self-improvement course would like such a course. The firm did a similar study 10 years ago in which 60% of a random sample of 160 salespeople wanted a self-improvement course. The groups are assumed to be independent random samples. Let π
1
and π
2
represent the true proportion of workers who would like to attend a self-improvement course in the recent study and the past study, respectively. -Referring to Instruction 10-12,if the firm wanted to test whether a greater proportion of workers would currently like to attend a self-improvement course than in the past,which represents the relevant hypotheses?
Question 168
True/False
Instruction 10-4 To test the effectiveness of a business school preparation course, 8 students took a general business test before and after the course. The results are given below.
Student
Exam Score
Before Course
Exam Score
After Course (2)
(
1
)
1
530
670
2
650
770
3
910
1
,
000
4
700
710
5
450
550
6
820
870
7
820
770
8
630
610
\begin{array} { c c c } \text { Student } & \begin{array} { c } \text { Exam Score } \\\text { Before Course }\end{array} & \begin{array} { c } \text { Exam Score } \\\text { After Course (2) }\end{array} \\& ( 1 ) & \\ 1 & 530 & 670 \\ 2 & 650 & 770 \\3 & 910 & 1,000 \\4 & 700 & 710 \\5 & 450 & 550 \\6 & 820 & 870 \\7 & 820 & 770 \\8 & 630 & 610\end{array}
Student
1
2
3
4
5
6
7
8
Exam Score
Before Course
(
1
)
530
650
910
700
450
820
820
630
Exam Score
After Course (2)
670
770
1
,
000
710
550
870
770
610
-Referring to Instruction 10-4,in examining the differences between related samples you are essentially sampling from an underlying population of difference "scores".
Question 169
Multiple Choice
Given the following information,calculate the degrees of freedom that should be used in the pooled-variance t test. S
1
2
= 4 S
2
2
= 6 N
1
= 16 n
2
= 25