Multiple Choice
In Drosophila,the genes crossveinless-c and Stubble are linked,about 7 map units apart on chromosome 3.cv-c is a recessive mutant allele of crossveinless-c (cv-c+ is wild type) ,while Sb is a dominant mutant allele of Stubble (Sb+ is wild type) . A dihybrid female Drosophila with genotype cv-c Sb+/cv-c+Sb is testcrossed.The proportion of phenotypically wild-type individuals in the progeny of the testcross will be:
A) 0.035.
B) 0.070.
C) 0.350.
D) 0.465.
E) 0.930.
Correct Answer:

Verified
Correct Answer:
Verified
Q1: An experiment was done to determine
Q2: Neurospora loci d and f are
Q3: A dihybrid in cis is crossed to
Q4: A second-division segregation ascus is an indication
Q5: The molecular process which results in the
Q7: Out of 800 progeny of a three-point
Q8: In unordered tetrad analyses of two linked
Q9: In one short chromosome arm the average
Q10: In the cross mt<sup>+</sup>al<sup>+</sup> <span
Q11: Draw a linkage map or maps consistent