For the Equilibrium N 2 O 4 (g) 2NO 2 (g),at 298 K,K p = 0$\times$

The Answer of For the Equilibrium N 2 O 4 (g) 2NO 2 (g),at 298 K,K p = 0$\times$

For the Equilibrium N 2 O 4 (g) 2NO 2 (g),at 298 K,K p = 0$\times$

The Answer of For the Equilibrium N 2 O 4 (g) 2NO 2 (g),at 298 K,K p = 0$\times$

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For the Equilibrium N₂O₄(g) 2NO₂(g),at 298 K,K_p = 0 $\times$

Question 53

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For the equilibrium N₂O₄(g) $For the equilibrium N2O4(g) 2NO2(g) ,at 298 K,Kp = 0.15.For this reaction system,it is found that the partial pressure of N2O4 is 3.6 \times 10-2 atm at equilibrium.What is the partial pressure of NO2 at equilibrium? A) 4.9 atm B) 24 atm C) 0.0017 atm D) 0.0054 atm E) 0.073 atm$ 2NO₂(g) ,at 298 K,K_p = 0.15.For this reaction system,it is found that the partial pressure of N₂O₄ is 3.6 $\times$ 10^-2 atm at equilibrium.What is the partial pressure of NO₂ at equilibrium?

A) 4.9 atm
B) 24 atm
C) 0.0017 atm
D) 0.0054 atm
E) 0.073 atm

For the Equilibrium N2O4(g) 2NO2(g),at 298 K,Kp = 0 ×\times×

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For the Equilibrium N₂O₄(g) 2NO₂(g),at 298 K,K_p = 0 $\times$

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