At 800 K,the Equilibrium Constant,K_p,for the Following Reaction Is $\times$ 10^-7 $\times$

Multiple Choice

At 800 K,the equilibrium constant,K_p,for the following reaction is
3.2 $\times$ 10^-7.2 H₂S(g) 2 H₂(g) + S₂(g)
A reaction vessel at 800 K initially contains 3.00 atm of H₂S.If the reaction is allowed to equilibrate,what is the equilibrium pressure of S₂?

A) 8.5 $\times$ 10^-5 atm
B) 6.2 $\times$ 10^-3 atm
C) 9.0 $\times$ 10^-3 atm
D) 1.1 $\times$ 10^-2 atm
E) 1.4 $\times$ 10^-2 atm