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What Is the Balanced Spontaneous Reaction and Standard Cell Potential \to

Question 54

Multiple Choice

What is the balanced spontaneous reaction and standard cell potential of an electrochemical cell constructed from half cells with the following half reactions?
Fe2+(aq) + 2e- \to Fe(s)         ~~~~~~~~        ~~~~~~~~ E° = -0.440 V
Pb2+(aq) + 2e- \to Pb(s)         ~~~~~~~~        ~~~~~~~~ E° = -0.130 V


A) Pb2+(aq) + Fe(s) \to Pb(s) + Fe2+(aq)  What is the balanced spontaneous reaction and standard cell potential of an electrochemical cell constructed from half cells with the following half reactions? Fe<sup>2+</sup>(aq) + 2e<sup>-</sup> \to  Fe(s)   ~~~~~~~~~~~~~~~~ E° = -0.440 V Pb<sup>2+</sup>(aq) + 2e<sup>-</sup> \to  Pb(s)   ~~~~~~~~~~~~~~~~ E° = -0.130 V A)  Pb<sup>2+</sup>(aq) + Fe(s)  \to Pb(s) + Fe<sup>2+</sup>(aq)    =0.310 V B)  Pb(s) + Fe<sup>2+</sup>(aq)  \to  Pb<sup>2+</sup>(aq) + Fe(s)    =-0.310 V C)  Pb<sup>2+</sup>(aq) + Fe<sup>2+</sup>(aq)  \to  Pb(s) + Fe(s)    =-0.570 V D)  Pb<sup>2+</sup>(aq) + Fe(s)  \to Pb(s) + Fe<sup>2+</sup>(aq)    =0.155 V E)  Pb(s) + Fe<sup>2+</sup>(aq)  \to  Pb<sup>2+</sup>(aq) + Fe(s)    =-0.155 V =0.310 V
B) Pb(s) + Fe2+(aq) \to Pb2+(aq) + Fe(s)  What is the balanced spontaneous reaction and standard cell potential of an electrochemical cell constructed from half cells with the following half reactions? Fe<sup>2+</sup>(aq) + 2e<sup>-</sup> \to  Fe(s)   ~~~~~~~~~~~~~~~~ E° = -0.440 V Pb<sup>2+</sup>(aq) + 2e<sup>-</sup> \to  Pb(s)   ~~~~~~~~~~~~~~~~ E° = -0.130 V A)  Pb<sup>2+</sup>(aq) + Fe(s)  \to Pb(s) + Fe<sup>2+</sup>(aq)    =0.310 V B)  Pb(s) + Fe<sup>2+</sup>(aq)  \to  Pb<sup>2+</sup>(aq) + Fe(s)    =-0.310 V C)  Pb<sup>2+</sup>(aq) + Fe<sup>2+</sup>(aq)  \to  Pb(s) + Fe(s)    =-0.570 V D)  Pb<sup>2+</sup>(aq) + Fe(s)  \to Pb(s) + Fe<sup>2+</sup>(aq)    =0.155 V E)  Pb(s) + Fe<sup>2+</sup>(aq)  \to  Pb<sup>2+</sup>(aq) + Fe(s)    =-0.155 V =-0.310 V
C) Pb2+(aq) + Fe2+(aq) \to Pb(s) + Fe(s)  What is the balanced spontaneous reaction and standard cell potential of an electrochemical cell constructed from half cells with the following half reactions? Fe<sup>2+</sup>(aq) + 2e<sup>-</sup> \to  Fe(s)   ~~~~~~~~~~~~~~~~ E° = -0.440 V Pb<sup>2+</sup>(aq) + 2e<sup>-</sup> \to  Pb(s)   ~~~~~~~~~~~~~~~~ E° = -0.130 V A)  Pb<sup>2+</sup>(aq) + Fe(s)  \to Pb(s) + Fe<sup>2+</sup>(aq)    =0.310 V B)  Pb(s) + Fe<sup>2+</sup>(aq)  \to  Pb<sup>2+</sup>(aq) + Fe(s)    =-0.310 V C)  Pb<sup>2+</sup>(aq) + Fe<sup>2+</sup>(aq)  \to  Pb(s) + Fe(s)    =-0.570 V D)  Pb<sup>2+</sup>(aq) + Fe(s)  \to Pb(s) + Fe<sup>2+</sup>(aq)    =0.155 V E)  Pb(s) + Fe<sup>2+</sup>(aq)  \to  Pb<sup>2+</sup>(aq) + Fe(s)    =-0.155 V =-0.570 V
D) Pb2+(aq) + Fe(s) \to Pb(s) + Fe2+(aq)  What is the balanced spontaneous reaction and standard cell potential of an electrochemical cell constructed from half cells with the following half reactions? Fe<sup>2+</sup>(aq) + 2e<sup>-</sup> \to  Fe(s)   ~~~~~~~~~~~~~~~~ E° = -0.440 V Pb<sup>2+</sup>(aq) + 2e<sup>-</sup> \to  Pb(s)   ~~~~~~~~~~~~~~~~ E° = -0.130 V A)  Pb<sup>2+</sup>(aq) + Fe(s)  \to Pb(s) + Fe<sup>2+</sup>(aq)    =0.310 V B)  Pb(s) + Fe<sup>2+</sup>(aq)  \to  Pb<sup>2+</sup>(aq) + Fe(s)    =-0.310 V C)  Pb<sup>2+</sup>(aq) + Fe<sup>2+</sup>(aq)  \to  Pb(s) + Fe(s)    =-0.570 V D)  Pb<sup>2+</sup>(aq) + Fe(s)  \to Pb(s) + Fe<sup>2+</sup>(aq)    =0.155 V E)  Pb(s) + Fe<sup>2+</sup>(aq)  \to  Pb<sup>2+</sup>(aq) + Fe(s)    =-0.155 V =0.155 V
E) Pb(s) + Fe2+(aq) \to Pb2+(aq) + Fe(s)  What is the balanced spontaneous reaction and standard cell potential of an electrochemical cell constructed from half cells with the following half reactions? Fe<sup>2+</sup>(aq) + 2e<sup>-</sup> \to  Fe(s)   ~~~~~~~~~~~~~~~~ E° = -0.440 V Pb<sup>2+</sup>(aq) + 2e<sup>-</sup> \to  Pb(s)   ~~~~~~~~~~~~~~~~ E° = -0.130 V A)  Pb<sup>2+</sup>(aq) + Fe(s)  \to Pb(s) + Fe<sup>2+</sup>(aq)    =0.310 V B)  Pb(s) + Fe<sup>2+</sup>(aq)  \to  Pb<sup>2+</sup>(aq) + Fe(s)    =-0.310 V C)  Pb<sup>2+</sup>(aq) + Fe<sup>2+</sup>(aq)  \to  Pb(s) + Fe(s)    =-0.570 V D)  Pb<sup>2+</sup>(aq) + Fe(s)  \to Pb(s) + Fe<sup>2+</sup>(aq)    =0.155 V E)  Pb(s) + Fe<sup>2+</sup>(aq)  \to  Pb<sup>2+</sup>(aq) + Fe(s)    =-0.155 V =-0.155 V

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