Essay
Aluminum metal dissolved in hydrochloric acid as follows:
2Al(s) + 6HCl(aq) 2AlCl3(aq) + 3H2(g)
a. What is the minimum volume of 6.0 M HCl(aq) needed to completely dissolve 3.20 g of aluminum in this reaction?
b. What mass of AlCl3 would be produced by complete reaction of 3.20 g of aluminum?
Correct Answer:
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a. 59.3 mL...View Answer
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Correct Answer:
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