Short Answer
Sulfuric acid (H2SO4) reacts with potassium hydroxide (KOH) as follows.
H2SO4(aq) + 2KOH(aq) K2SO4(aq) + 2H2O(l)
Calculate the volume of 0.100 M sulfuric acid required to neutralize 25.0 mL of 0.0821 M KOH. Show all your work.
Correct Answer:
Verified
Correct Answer:
Verified
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