Use Long Division to Find the Quotient and the Remainder $\frac { 6 x ^ { 3 } - 3 x + 3 } { 2 x + 1 }$

Multiple Choice

Use long division to find the quotient and the remainder. $\frac { 6 x ^ { 3 } - 3 x + 3 } { 2 x + 1 }$

A) $\text { quotient: } 3 x ^ { 2 } - \frac { 3 } { 2 } x - \frac { 3 } { 4 } ; \text { remainder: } \frac { 15 } { 4 }$
B) $\text { quotient: } 3 x ^ { 2 } - \frac { 3 } { 2 } x + \frac { 1 } { 4 } ; \text { remainder: } \frac { 15 } { 4 }$
C) $\text { quotient: } 15 x ^ { 2 } + \frac { 3 } { 2 } x - \frac { 1 } { 4 } ; \text { remainder: } \frac { 3 } { 4 }$
D) $\text { quotient: } 3 x ^ { 2 } - \frac { 3 } { 2 } x - \frac { 3 } { 4 } ; \text { remainder: } - \frac { 15 } { 4 }$
E) $\text { quotient: } 3 x ^ { 2 } - \frac { 3 } { 2 } x - \frac { 3 } { 4 } ; \text { remainder: } \frac { 7 } { 4 }$