Find the Particular Solution of the Given Differential Equation That $\frac { d y } { d x } = y ^ { 2 } \sqrt { 6 - x }$

Multiple Choice

Find the particular solution of the given differential equation that satisfies the indicated condition: $\frac { d y } { d x } = y ^ { 2 } \sqrt { 6 - x }$ ; y = 1 when x = 6.

A) $y = \frac { 2 ( 6 - x ) ^ { 3 / 2 } - 3 } { 3 }$
B) $y = \frac { 3 } { 2 ( 6 + x ) ^ { 3 / 2 } - 3 }$
C) $y = \frac { 3 } { 2 ( 6 - x ) ^ { 3 / 2 } - 3 }$
D) $y = \frac { 3 } { 2 ( 6 - x ) ^ { 3 / 2 } + 3 }$