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Suppose 2 x3x ^ { 3 } - 3 p4p ^ { 4 }

Question 50

Multiple Choice

Suppose 2 x3x ^ { 3 } - 3 p4p ^ { 4 } = 6, where x and p are differentiable functions of t. Find dpdt\frac { \mathrm { dp } } { \mathrm { dt } } .


A) 6 x2x ^ { 2 } dxdt\frac { \mathrm { dx } } { \mathrm { dt } } - 12 p3p ^ { 3 }
B) 66x212p3\frac { 6 - 6 x ^ { 2 } } { 12 p ^ { 3 } } dxdt\frac { \mathrm { dx } } { \mathrm { dt } }
C) 6 x2x ^ { 2 } - 12 p3p ^ { 3 } dpdt\frac { \mathrm { dp } } { \mathrm { dt } }
D) x22p3\frac { x ^ { 2 } } { 2 p ^ { 3 } } dxdt\frac { \mathrm { dx } } { \mathrm { dt } }

Correct Answer:

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