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Find the Equation of the Line Tangent to the Graph x2y3=1 at the point (1,1)x ^ { 2 } y ^ { 3 } = 1 \text { at the point } ( 1,1 )

Question 55

Short Answer

Find the equation of the line tangent to the graph of x2y3=1 at the point (1,1)x ^ { 2 } y ^ { 3 } = 1 \text { at the point } ( 1,1 ) Enter your answer in slope-intercept form.

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