F(x) = $x ^ { 5 }$ + X - 3 Has a Zero Between 1 and 3

Short Answer

f(x) = $x ^ { 5 }$ + x - 3 has a zero between 1 and 2 .
Use two repetitions of the Newton-Raphson algorithm to approximate this zero with $x _ { 0 } = 1$ Enter just a real number rounded off to two decimal places.