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Given the Differential Equation y=y2t2y2y ^ { \prime } = y ^ { 2 } - t ^ { 2 } y ^ { 2 }

Question 107

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Given the differential equation: y=y2t2y2y ^ { \prime } = y ^ { 2 } - t ^ { 2 } y ^ { 2 } , is this the solution: y=113t3t+C?y = \frac { 1 } { \frac { 1 } { 3 } t ^ { 3 } - t + C } ?

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