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Given the Differential Equation (t+1)y=yt2y( t + 1 ) y ^ { \prime } = y t ^ { 2 } - y

Question 103

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Given the differential equation: (t+1)y=yt2y( t + 1 ) y ^ { \prime } = y t ^ { 2 } - y is this the solution y=cet2/2?y = c \mathrm { et } ^ { 2 } / 2 ?

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