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Solve the Differential Equation with the Given Initial Condition y=3t2(4y)2,y(0)=2y ^ { \prime } = 3 t ^ { 2 } ( 4 - y ) ^ { 2 } , y ( 0 ) = 2

Question 59

Multiple Choice

Solve the differential equation with the given initial condition.
- y=3t2(4y) 2,y(0) =2y ^ { \prime } = 3 t ^ { 2 } ( 4 - y ) ^ { 2 } , y ( 0 ) = 2


A) y = 4 - 1t3+12\frac { 1 } { t ^ { 3 } + \frac { 1 } { 2 } }
B) y = 1t3+2\frac { 1 } { t ^ { 3 } + 2 }
C) y = t3t ^ { 3 } + 12\frac { 1 } { 2 }
D) y = 4 + t3t ^ { 3 }

Correct Answer:

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