Given the Differential Equation with the Given Initial Condition $y ^ { \prime } = e ^ { - y } ; \quad y ( 0 ) = 0$

True/False

Given the differential equation with the given initial condition: $y ^ { \prime } = e ^ { - y } ; \quad y ( 0 ) = 0$ is this the solution $y = \ln | t + 1 | ?$