Find the First Derivative of Z = 4t + (3 $\sqrt { 2 t + 1 }$

Short Answer

Find the first derivative of z = 4t + (3 - $\sqrt { 2 t + 1 }$ $) ^ { 3 }$ at t = $\frac { 3 } { 2 }$ .
Enter just a fraction of form $\frac { a } { b }$ in lowest terms.