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Find Pk + 1 for the Given Pk pk=6k(k+1)p _ { k } = \frac { 6 } { k ( k + 1 ) }

Question 6

Multiple Choice

Find pk + 1 for the given pk.​ pk=6k(k+1) p _ { k } = \frac { 6 } { k ( k + 1 ) }


A) pk+1=2k(k+2) p _ { k + 1 } = \frac { 2 } { k ( k + 2 ) }
B) pk+1=6(k+1) (k+1) p _ { k + 1 } = \frac { 6 } { ( k + 1 ) ( k + 1 ) }
C) pk+1=6(k+1) (k+2) p _ { k + 1 } = \frac { 6 } { ( k + 1 ) ( k + 2 ) }
D) pk+1=6(k+2) (k+6) p _ { k + 1 } = \frac { 6 } { ( k + 2 ) ( k + 6 ) }
E) pk+1=6k(k+2) p _ { k + 1 } = \frac { 6 } { k ( k + 2 ) }

Correct Answer:

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