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Find Pk + 1 for the Given Pk pk=k2(k+4)28p _ { k } = \frac { k ^ { 2 } ( k + 4 ) ^ { 2 } } { 8 }

Question 2

Multiple Choice

Find pk + 1 for the given pk .​ pk=k2(k+4) 28p _ { k } = \frac { k ^ { 2 } ( k + 4 ) ^ { 2 } } { 8 }


A) pk+1=(k+1) 2(k+5) 28p _ { k + 1 } = \frac { ( k + 1 ) ^ { 2 } ( k + 5 ) ^ { 2 } } { 8 }
B) pk+1=k2(k+5) 28p _ { k + 1 } = \frac { k ^ { 2 } ( k + 5 ) ^ { 2 } } { 8 }
C) pk+1=(k+1) 2(k+5) 29p _ { k + 1 } = \frac { ( k + 1 ) ^ { 2 } ( k + 5 ) ^ { 2 } } { 9 }
D) pk+1=(k+1) 2(k+9) 28p _ { k + 1 } = \frac { ( k + 1 ) ^ { 2 } ( k + 9 ) ^ { 2 } } { 8 }
E) pk+1=k2(k+9) 28p _ { k + 1 } = \frac { k ^ { 2 } ( k + 9 ) ^ { 2 } } { 8 }

Correct Answer:

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