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Solve the Following Equation cos2x(4cosx+2)=0\cos 2 x ( 4 \cos x + 2 ) = 0

Question 18

Multiple Choice

Solve the following equation.​ cos2x(4cosx+2) =0\cos 2 x ( 4 \cos x + 2 ) = 0


A) 4π3+nπ,2π3+nπ,4π3+2nπ\frac { 4 \pi } { 3 } + n \pi , \frac { 2 \pi } { 3 } + n \pi , \frac { 4 \pi } { 3 } + 2 n \pi
B) ​ π4+nπ2,2π3+2nπ,4π3+2nπ\frac { \pi } { 4 } + \frac { n \pi } { 2 } , \frac { 2 \pi } { 3 } + 2 n \pi , \frac { 4 \pi } { 3 } + 2 n \pi
C) ​ π3+nπ,π3+nπ\frac { \pi } { 3 } + n \pi , \frac { \pi } { 3 } + n \pi
D) ​ π2+nπ,2π5+nπ\frac { \pi } { 2 } + n \pi , \frac { 2 \pi } { 5 } + n \pi
E) ​ 2π3+nπ,2π3+nπ\frac { 2 \pi } { 3 } + n \pi , \frac { 2 \pi } { 3 } + n \pi

Correct Answer:

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