By using a graphing utility to complete the following table.Round your answer to two decimal places.

\begin{array} { | l | l | l | l | l | l | l | l | } \hline x & 0.2 & 0.4 & 0.6 & 0.8 & 1 & 1.2 & 1.4 \\\hline y _ { 1 } & - & - & - & - & - & - & - \\\hline y _ { 2 } & - & - & - & - & - & - & - \\\hline\end{array}

y _ { 1 } = \sec ^ { 4 } x - \sec ^ { 2 } x , y _ { 2 } = \tan ^ { 2 } x \sec ^ { 2 } x

\begin{array} { | l | l | l | l | l | l | l | l | } \hline x & 0.2 & 0.4 & 0.6 & 0.8 & 1 & 1.2 & 1.4 \\\hline y _ { 1 } & - 0.04 & 0.21 & 0.69 & 2.18 & 8.31 & 50.39 & 1,163.61 \\\hline y _ { 2 } & - 0.04 & 0.21 & 0.69 & 2.18 & 8.31 & 50.39 & 1,163.61 \\\hline\end{array}

\begin{array} { | l | l | l | l | l | l | l | l | } \hline x & 0.2 & 0.4 & 0.6 & 0.8 & 1 & 1.2 & 1.4 \\\hline y _ { 1 } & 0.04 & 0.21 & 0.69 & 2.18 & 8.31 & 50.39 & 1,163.61 \\\hline y _ { 2 } & 0.04 & 0.21 & 0.69 & 2.18 & 8.31 & 50.39 & 1,163.61 \\\hline\end{array}

\begin{array} { | l | l | l | l | l | l | l | l | } \hline x & 0.2 & 0.4 & 0.6 & 0.8 & 1 & 1.2 & 1.4 \\\hline y _ { 1 } & 0.04 & 0.21 & 0.69 & - 2.18 & 8.31 & 50.39 & 1,163.61 \\\hline y _ { 2 } & 0.04 & 0.21 & 0.69 & - 2.18 & 8.31 & 50.39 & 1,163.61 \\\hline\end{array}

\begin{array} { | l | l | l | l | l | l | l | l | } \hline x & 0.2 & 0.4 & 0.6 & 0.8 & 1 & 1.2 & 1.4 \\\hline y _ { 1 } & 0.04 & 0.21 & - 0.69 & 2.18 & 8.31 & 50.39 & 1,163.61 \\\hline y _ { 2 } & 0.04 & 0.21 & - 0.69 & 2.18 & 8.31 & 50.39 & 1,163.61 \\\hline\end{array}

\begin{array} { | l | l | l | l | l | l | l | l | } \hline x & 0.2 & 0.4 & 0.6 & 0.8 & 1 & 1.2 & 1.4 \\\hline y _ { 1 } & 0.04 & 0.21 & 0.69 & 2.18 & 8.31 & 50.39 & - 1,163.61 \\\hline y _ { 2 } & 0.04 & 0.21 & 0.69 & 2.18 & 8.31 & 50.39 & - 1,163.61 \\\hline\end{array}

Use the Trigonometric Substitution to Rewrite the Algebraic Expression as a Trigonometric

Multiple Choice