Evaluate (If Possible)the Sine,cosine,and Tangent of the Real Number $t = \frac { 9 \pi } { 4 }$

Multiple Choice

Evaluate (if possible) the sine,cosine,and tangent of the real number.​ $t = \frac { 9 \pi } { 4 }$ ​

A) $t = \frac { 9 \pi } { 4 }$ corresponds to the point $( x , y ) = \left( \frac { \sqrt { 2 } } { 2 } , - \frac { \sqrt { 2 } } { 2 } \right)$ . $\begin{array} { l } \sin \left( \frac { 9 \pi } { 4 } \right) = - \frac { \sqrt { 2 } } { 2 } \\\cos \left( \frac { 9 \pi } { 4 } \right) = \frac { \sqrt { 2 } } { 2 } \\\tan \left( \frac { 9 \pi } { 4 } \right) = - 1\end{array}$
B) $t = \frac { 9 \pi } { 4 }$ corresponds to the point $( x , y ) = \left( \frac { \sqrt { 2 } } { 2 } , \frac { \sqrt { 2 } } { 2 } \right)$ . $\begin{array} { l } \sin \left( \frac { 9 \pi } { 4 } \right) = \frac { \sqrt { 2 } } { 2 } \\\cos \left( \frac { 9 \pi } { 4 } \right) = \frac { \sqrt { 2 } } { 2 } \\\tan \left( \frac { 9 \pi } { 4 } \right) = 1\end{array}$ ​
C) $t = \frac { 9 \pi } { 4 }$ corresponds to the point $( x , y ) = \left( - \frac { \sqrt { 2 } } { 2 } , - \frac { \sqrt { 2 } } { 2 } \right)$ . $\begin{array} { l } \sin \left( \frac { 9 \pi } { 4 } \right) = - \frac { \sqrt { 2 } } { 2 } \\\cos \left( \frac { 9 \pi } { 4 } \right) = - \frac { \sqrt { 2 } } { 2 } \\\tan \left( \frac { 9 \pi } { 4 } \right) = 1\end{array}$ ​
D) $t = \frac { 9 \pi } { 4 }$ corresponds to the point $( x , y ) = \left( - \frac { \sqrt { 2 } } { 2 } , \frac { \sqrt { 2 } } { 2 } \right)$ .​ $\begin{array} { l } \sin \left( \frac { 9 \pi } { 4 } \right) = \frac { \sqrt { 2 } } { 2 } \\\cos \left( \frac { 9 \pi } { 4 } \right) = - \frac { \sqrt { 2 } } { 2 } \\\tan \left( \frac { 9 \pi } { 4 } \right) = - 1\end{array}$
E) Not possible