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The Spread of a Contaminant Is Increasing in a Circular r(t)=2.25tr ( t ) = 2.25 \sqrt { t }

Question 3

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The spread of a contaminant is increasing in a circular pattern on the surface of a lake.The radius of the contaminant can be modeled by r(t) =2.25tr ( t ) = 2.25 \sqrt { t } ,where r is the radius in meters and t is the time in hours since contamination. ​
Find a function that gives the area A of the circular lake in terms of the time since the spread began.


A) Ar(t) =5.0625πtA \circ r ( t ) = 5.0625 \pi \sqrt { t }
B) Ar(t) =2.25πtA \circ r ( t ) = 2.25 \pi t
C) Ar(t) =5.0625tA \circ r ( t ) = 5.0625 t
D) Ar(t) =5.0625tA \circ r ( t ) = 5.0625 \sqrt { t }
E) Ar(t) =5.0625πtA \circ r ( t ) = 5.0625 \pi t

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