Use the given value of k to complete the table for the inverse variation model

y = \frac { k } { x ^ { 2 } }

Plot the points on a rectangular coordinate system.

\begin{array}{l}\begin{array} { | c | c | c | c | c | c | } \hline x & 2 & 4 & 6 & 8 & 10 \\\hline y = \frac { k } { x ^ { 2 } } & & & & & \\\hline\end{array}\\k = 2\end{array}

\begin{array} { | c | c | c | c | c | c | } \hline x & 2 & 4 & 6 & 8 & 10 \\\hline y = \frac { k } { x ^ { 2 } }& \frac { 1 } { 2 } & \frac { 1 } { 8 } & \frac { 1 } { 18 } & \frac { 1 } { 32 } & \frac { 1 } { 50 } \\\hline\end{array}

$Use the given value of k to complete the table for the inverse variation model y = \frac { k } { x ^ { 2 } } Plot the points on a rectangular coordinate system. \begin{array}{l} \begin{array} { | c | c | c | c | c | c | } \hline x & 2 & 4 & 6 & 8 & 10 \\ \hline y = \frac { k } { x ^ { 2 } } & & & & & \\ \hline \end{array}\\ k = 2 \end{array} A) \begin{array} { | c | c | c | c | c | c | } \hline x & 2 & 4 & 6 & 8 & 10 \\ \hline y = \frac { k } { x ^ { 2 } }& \frac { 1 } { 2 } & \frac { 1 } { 8 } & \frac { 1 } { 18 } & \frac { 1 } { 32 } & \frac { 1 } { 50 } \\ \hline \end{array} B) \begin{array} { | c | c | c | c | c | c | } \hline x & 2 & 4 & 6 & 8 & 10 \\ \hline y = \frac { k } { x ^ { 2 } } & \frac { 1 } {2 }&\frac { 1 } {2 } &\frac { 1 } {2 } & \frac { 1 } {2 }&\frac { 1 } {2 } \\ \hline \end{array} C) \begin{array} { | c | c | c | c | c | c | } \hline x & 2 & 4 & 6 & 8 & 10 \\ \hline y = \frac { k } { x ^ { 2 } } & & & & & \\ & \frac { 1 } { 50 } & \frac { 1 } { 32 } & \frac { 1 } { 18 } & \frac { 1 } { 8 } & \frac { 1 } { 2 } \\\\ \hline \end{array} D) \begin{array} { | c | c | c | c | c | c | } \hline x & 2 & 4 & 6 & 8 & 10 \\ \hline y = k x ^ { 2 } & & & & & \\ & \frac { 1 } { 2 } & \frac { 1 } { 8 } & \frac { 1 } { 18 } & \frac { 1 } { 8 } & \frac { 1 } { 2 } \\\\ \hline \end{array} E) \begin{array} { | c | c | c | c | c | c | } \hline x & 2 & 4 & 6 & 8 & 10 \\ \hline y = \frac { k } { x ^ { 2 } } &2 & 4& 6& 8&10 \\ \hline \end{array} $
B)

\begin{array} { | c | c | c | c | c | c | } \hline x & 2 & 4 & 6 & 8 & 10 \\\hline y = \frac { k } { x ^ { 2 } } & \frac { 1 } {2 }&\frac { 1 } {2 } &\frac { 1 } {2 } & \frac { 1 } {2 }&\frac { 1 } {2 } \\\hline\end{array}

\begin{array} { | c | c | c | c | c | c | } \hline x & 2 & 4 & 6 & 8 & 10 \\\hline y = \frac { k } { x ^ { 2 } } & & & & & \\& \frac { 1 } { 50 } & \frac { 1 } { 32 } & \frac { 1 } { 18 } & \frac { 1 } { 8 } & \frac { 1 } { 2 } \\\\\hline\end{array}

\begin{array} { | c | c | c | c | c | c | } \hline x & 2 & 4 & 6 & 8 & 10 \\\hline y = k x ^ { 2 } & & & & & \\& \frac { 1 } { 2 } & \frac { 1 } { 8 } & \frac { 1 } { 18 } & \frac { 1 } { 8 } & \frac { 1 } { 2 } \\\\\hline\end{array}

\begin{array} { | c | c | c | c | c | c | } \hline x & 2 & 4 & 6 & 8 & 10 \\\hline y = \frac { k } { x ^ { 2 } } &2 & 4& 6& 8&10 \\\hline\end{array}

Assume That Y Is Directly Proportional to X x=5,y=24x = 5 , y = 24x=5,y=24

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Assume That Y Is Directly Proportional to X $x = 5 , y = 24$

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