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The Solution Of x2y+3xy3y=0x ^ { 2 } y ^ { \prime \prime } + 3 x y ^ { \prime } - 3 y = 0

Question 21

Multiple Choice

The solution of x2y+3xy3y=0x ^ { 2 } y ^ { \prime \prime } + 3 x y ^ { \prime } - 3 y = 0 is


A) y=c1x+c2x3y = c _ { 1 } x + c _ { 2 } x ^ { - 3 }
B) y=c1x1+c2x3y = c _ { 1 } x ^ { - 1 } + c _ { 2 } x ^ { 3 }
C) y=c1ex+c2e3xy = c _ { 1 } e ^ { x } + c _ { 2 } e ^ { - 3 x }
D) y=c1ex+c2e3xy = c _ { 1 } e ^ { - x } + c _ { 2 } e ^ { 3 x }
E) y=c1x+c2x3y = c _ { 1 } x + c _ { 2 } x ^ { 3 }

Correct Answer:

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